ex48——更复杂的用户输入/扫描输入

lexicon程序

defconvert_number(s):"""处理异常和数字的函数"""try:returnint(s)exceptValueError:returnNoneclassLexicon():# 因主程序中调用的是lexicon.scan(),因此只能是由定义类的属性延伸到函数的属性""" 功能介绍： 1. 名称：lexicon 2. 实参：用户输入的字符串 3. 返回值return：语汇元组格式 4. 若单词不在单词语汇表中，返回原单词 5. TOKEN错误标记，标记用户错误的地方 """def__init__(self):# 初始化，并设置单词语汇表self.direction=['north','south','east','west','down','up','left','right','back']self.verb=['go','stop','kill','eat']self.stop=['the','in','of','from','at','it']self.noun=['door','bear','princess','cabinet']defscan(self,stuff):# 定义方法scansentence=[]words=stuff.split()forwordinwords:ifwordinself.direction:sentence.append(('direction',word))elifwordinself.verb:sentence.append(('verb',word))elifwordinself.stop:sentence.append(('stop',word))elifwordinself.noun:sentence.append(('noun',word))elifconvert_number(word):sentence.append(('numb',int(word)))else:sentence.append(('error',word))returnsentence# lexicon是否有更好的调用方法？？？lexicon=Lexicon()

fromnose.toolsimport*fromex48importlexicondeftest_direction():# lexicon.scan(str)意味着对函数lexicon添加了属性，需要借用类的概念。# 类的其中一个方法是scanassert_equal(lexicon.scan("north"),[('direction','north')])result=lexicon.scan("north south east")assert_equal(result,[('direction','north'),('direction','south'),('direction','east')],)deftest_verbs():assert_equal(lexicon.scan("go"),[('verb','go')])result=lexicon.scan("go kill eat")assert_equal(result,[('verb','go'),('verb','kill'),('verb','eat')])deftest_stops():assert_equal(lexicon.scan("the"),[('stop','the')])result=lexicon.scan("the in of")assert_equal(result,[('stop','the'),('stop','in'),('stop','of')])deftest_nouns():assert_equal(lexicon.scan("bear"),[('noun','bear')])result=lexicon.scan("bear princess")assert_equal(result,[('noun','bear'),('noun','princess')])deftest_numbers():# 输入的整数第一个单位不能为0assert_equal(lexicon.scan("1234"),[('numb',1234)])result=lexicon.scan("12 432")assert_equal(result,[('numb',12),('numb',432)])deftest_errors():# 若输入的单词不在语汇表中，则保持原样返回，并报错显示其位置assert_equal(lexicon.scan("asdf23"),[('error','asdf23')])result=lexicon.scan("bear IAS princess 806")assert_equal(result,[('noun','bear'),('error','IAS'),('noun','princess'),('numb',806)])